Laura Cristina 08/06/2023 at 6:05 pm [(5×5^(2n+2)-5^(2+2n)]/[(5×5^(2n+3)-5^(2n+2)]= [5^(2n+2)(5-1)]/[5²×5^(2n)(5-1)(5+1)]= (5^2n×5²)/(5²×5^2n×6)= 1/6** Reply
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1/6 6 or 6^-1
[(5×5^(2n+2)-5^(2+2n)]/[(5×5^(2n+3)-5^(2n+2)]=
[5^(2n+2)(5-1)]/[5²×5^(2n)(5-1)(5+1)]=
(5^2n×5²)/(5²×5^2n×6)= 1/6**