The probability of a shooter hitting a target is 0.75. How many (minimum) number of times must he fire so that the probability of hitting the target at least once is more than 0.99?
The probability of a shooter hitting a target is 0.75. How many (minimum) number of times must he fire so that the probability of hitting the target at least once is more than 0.99?
4 ori
Since chances of not hitting the target is 0.25, then
0.25^y=(1-0.99)
0.25^y=0.01
y(log.25)=y(log .01)
y=-2/-.602
y=3.3
He has to have more than 3 tries so the least is 4 times.
Lovely
The probability of missing all of the n shots is (1/4)^n, and it should be less then 1/100.
So 4^3=64, 4^4=128.
Then after 4 shots the probability of hitting at least one shot is greater then 0,99
99times
Atleast 4