Let the original price of an item be
x
Let the number of items be y
(x+5)(y-2)=200…(i)
xy=200..(ii)
y=200/x..(iii)
From (i)
xy-2x+5y-10=200..(iv)
Substitute (iii) in (iv)
x(200/x)-2x+1000/x-210=0
200-210-2x+1000/x=0
-10-2x+1000/x=0
-10x-2x²+1000=0
x²+5x-500=0
x²+25x-20x-500=0
x(x+25)-20(x+25)=0
(x-20)(x+25)=0
But x≠-25 since x>0
Therefore
x=sh 20
y=200/20=10 items
Let the original price of an item be
x
Let the number of items be y
(x+5)(y-2)=200…(i)
xy=200..(ii)
y=200/x..(iii)
From (i)
xy-2x+5y-10=200..(iv)
Substitute (iii) in (iv)
x(200/x)-2x+1000/x-210=0
200-210-2x+1000/x=0
-10-2x+1000/x=0
-10x-2x²+1000=0
x²+5x-500=0
x²+25x-20x-500=0
x(x+25)-20(x+25)=0
(x-20)(x+25)=0
But x≠-25 since x>0
Therefore
x=sh 20
y=200/20=10 items
Good question!!