Equation maths Num xxx

Need help question number 6

2 thoughts on “Equation maths Num xxx”

  1. Let the original price of an item be
    x
    Let the number of items be y
    (x+5)(y-2)=200…(i)
    xy=200..(ii)
    y=200/x..(iii)
    From (i)
    xy-2x+5y-10=200..(iv)
    Substitute (iii) in (iv)
    x(200/x)-2x+1000/x-210=0
    200-210-2x+1000/x=0
    -10-2x+1000/x=0
    -10x-2x²+1000=0
    x²+5x-500=0
    x²+25x-20x-500=0
    x(x+25)-20(x+25)=0
    (x-20)(x+25)=0
    But x≠-25 since x>0
    Therefore
    x=sh 20
    y=200/20=10 items

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